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On Sat, 27 Oct 2007 01:45:25 -0700, "Green Xenon [Radium]"
wrote: Dave Platt wrote: In article , Green Xenon [Radium] wrote: So there is no way to decrease how far the sidebands will go? With FM? Nope, not in the way you're hoping. Modulate a carrier Fc with a frequency Fm, and the first sidebands will be at Fc+Fm and Fc-Fm, just as would be true with AM. That's the narrowest you can get. So a higher-frequency modulation signal will result in more distant sidebands than a lower-frequency modulation signal? E.g. a 10,000 Hz tone will result in sidebands further from the base carrier frequency than a 1,000 Hz signal? No, this is not true. Both the 10,000 Hz and the 1,000 Hz tones will produce sidebands which extend to infinity. |
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#2
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In article , George
wrote: On Sat, 27 Oct 2007 01:45:25 -0700, "Green Xenon [Radium]" wrote: So a higher-frequency modulation signal will result in more distant sidebands than a lower-frequency modulation signal? E.g. a 10,000 Hz tone will result in sidebands further from the base carrier frequency than a 1,000 Hz signal? No, this is not true. ...although it will be the case with the 10kHz modulation that none of the sidebands will be closer than 10kHz from the carrier. Whereas with 1kHz modulation they will start at 1kHz. Both the 10,000 Hz and the 1,000 Hz tones will produce sidebands which extend to infinity. That is what textbooks say about an ideal case of one sinusoid modulated with another. But I suspect the posting you responded to assumed that we were talking about sideband components with power levels significant enough to matter in relevant real-world situations. Possibly even assuming the same sort of peak deviation level without saying so. ;- Fortunately: A) The amplitude of the sideband components tends to fall rapidly towards infinitesimally small as you move very far away from the carrier. Bessel functions of the relevant type are like that. B) Real world situations generally don't use ideal sinusoids, nor require zero distortion. Nor use modulators and demodulators with infinite bandwidths. Thus real modulation bandwiths have a tendency to be finite. Thus reality only approximates to the simple textbook analysis you base your statement upon. (Most texts avoid more complex modulations and the effect of finite TX bandwidths like the plague as they can be a nightmare to model analytically or explain, certainly at an undergrad level! The tendency is to do simple mod, quote Carson's Rule, and quit while you are ahead. :-) ) So - unless your interest is purely in trying to score a debating point by nit-picking based simplifying what appears in undergrad texts - what was your point? :-) Slainte, Jim -- Electronics http://www.st-and.ac.uk/~www_pa/Scot...o/electron.htm Audio Misc http://www.audiomisc.co.uk/index.html Armstrong Audio http://www.audiomisc.co.uk/Armstrong/armstrong.html |
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#3
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On Sat, 27 Oct 2007 17:56:13 +0100, Jim Lesurf
wrote: So - unless your interest is purely in trying to score a debating point by nit-picking based simplifying what appears in undergrad texts - what was your point? :-) Slainte, Jim If you examine this thread you might conclude that the question was asked by someone seeking knowledge. The first respondant took advantage of this to provide a sarcastic put-down, which, incidentally, exposed his own ignorance. Can you imagine the feelings of the questioner upon reading that response to his honest question ? That response was typical of many postings in this flaming Newgroup. Your own posting is made entirely in the same spirit and you should be ashamed. By George. |
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#4
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In article , George
wrote: On Sat, 27 Oct 2007 17:56:13 +0100, Jim Lesurf wrote: So - unless your interest is purely in trying to score a debating point by nit-picking based simplifying what appears in undergrad texts - what was your point? :-) Slainte, Jim If you examine this thread you might conclude that the question was asked by someone seeking knowledge. If you examine the thread *in uk.tech.digital.tv* where I am reading and replying, you will see that the start of the discussion was missing as only some responses have been posted here. Afraid my conclusions are only based on what has been posted where I read it. The first respondant took advantage of this to provide a sarcastic put-down, which, incidentally, exposed his own ignorance. Can you imagine the feelings of the questioner upon reading that response to his honest question ? It might help if you addressed what I wrote about *your* posting. :-) I was 'imagining' the feelings of the person whose posting I saw you dismiss as untrue when you said that, but didn't give an explanation which would have helped him to understand that, or your comment. That response was typical of many postings in this flaming Newgroup. Not clear which "flaming Newsgroup" you mean here. Your own posting is made entirely in the same spirit and you should be ashamed. As things stand I am unable to comment. I am sorry if you are upset, but perhaps you should have explained more clearly when you dismissed what someone else as not being "true". That way the "spirit" of your contribution would have been seen by me as being helpful rather than - as here - critical. :-) Slainte, Jim -- Electronics http://www.st-and.ac.uk/~www_pa/Scot...o/electron.htm Audio Misc http://www.audiomisc.co.uk/index.html Armstrong Audio http://www.audiomisc.co.uk/Armstrong/armstrong.html |
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#5
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In article , Green Xenon
[Radium] wrote: Sorry but I am now confused. Dave said that a higher-frequency modulator signal will result in wider sidebands than a lower-frequency modulator signal. George says no to that. Jim then goes on about how it may or may not be true. I am getting really confused. Will someone please assist me in clearing this up? The problem here is that what 'George' said may well have confused your understanding by introducting a point which is textbook correct, but was misleading for you in this context without other information. That is why I responded to him as I did, as I have see similar problems on many occasions when undergrads have been confused in similar ways. Teaching requires judgement about how you explain things, as well as patient effort by the learner. :-) To actually understand it is generally useful to start with a simplified description and then only add in details later in a way that builds on the initial, established, understanding. The snag is that this allows people to nit-pick and point-score to show off how clever they are, but risks confusing the person who wanted to learn, or make them think it is all to complex for them to follow. There is a fuller explanation of this in textbooks, and on the 'Scots Guide' (address in my sig, below). But that is aimed at the undergrad level student and assumes you're happy with the maths, so here is something simpler. Consider an example. Take a 1MHz sinusoid and modulate its frequency. This 1MHz signal is often called the 'carrier' and we'd then say we have a 'carrier frequency' in this case of 1MHz. Consider applying modulation with a 1kHz sinusoid as the modulation waveform. When considered as a sprectrum the result can be described as a series of 'sideband' components, spaced 1 kHz apart, centered on the carrier frequency. So we'd get components at 1MHz + 1kHz, 1MHz + 2kHz, 1MHz + 3kHz, etc. Also at 1MHz - 1kHz, 1MHz - 2 kHz, etc... In general, there will also still be a component at 1MHz. The general rule is that the components are spaced at intervals equal to the modulation frequency. So if we'd used 10kHz modulation instead, then the sideband components closest to the carrier would have been at 1MHz +/- 10kHz, the others at +/-20, +/- 30, etc... Thus the interval between them has changed. From the maths in the textbooks, these components nominally extend over an infinite frequency range. But in reality they don't, and they amplitudes tend to fall away to being insignificant when you look at frequencies a long long way from the carrier. The distribution of the amplitudes or powers of the components depends on how large the modulation is, as well as the modulation frequency. So, all else being equal, if you apply, say, 10kHz modulation, the components with significant power levels will tend to spread out over a wider range of frequencies than if we'd used 1kHz modulation. The precise meaning of "significant power levels" will depend on the use the FM system is being put to, and the conditions in which it is used. However a general rule-of-thumb people use is 'Carson's Rule'. (If interested in that, look for it on the Scots Guide.) Thus the point you made in your first posting in this thread *as it has appeared in the uk.tech.digital-tv group* is close to being correct, but there are problems with your wording which would need clarifying. All else being kept the same, Increasing the modulation frequency tends to spread out the sideband power distribution and thus requires a wider bandwidth. In practice a wider bandwidth tends to be required. But purely in terms of undergrad textbooks, any sinusoidal modulation of a sinusoid tends to give 'components' over an *infinite* range, so on that basis what 'George' said is formally correct, and your wording wrong. Since the components theoretically extend over an 'infinite' range, you can't say that increasing the modulation frequency will "result in sidebands further from the carrier" without qualifying that in some way like allowing for the power levels, or some equivalent. What happens that the distribution of power tends to spread out over a wider range of frequencies. (And hence the information also tends to do so.) The points he omitted are that some of [1] these 'components' well away from the carrier may be of a size close enough to zero to be of no real relevance, and that in real world systems no modulator or demodulator can produce 'infinite' bandwidths. Thus he was showing he'd read the textbooks which you hadn't, but confused you in the process. He was introducing the formal need in the maths for an infinite set of components, where many/most [1 again] of them will be infinitestimally small in power. It would have been better if he'd then explained this, rather than simply pronouncing that your comment wasn't "true". That way, his posting would have been more helpful, rather than confusing for you. But it is always easier - and quicker - to say someone else is wrong than it is to try to give a useful explanation yourself. Explanations like this take time, and may simply prompt someone else to nit-pick. :-) If you want an example of how the modulation frequency affects the spectrum, have a look at http://www.st-and.demon.co.uk/temp/fmspectra.html note, though, that this page was produced for another purpose so uses more complicated modulations than a simple sinusoid. In this case to show the effect of stereo (difference) modulation on traditional stereo FM broadcasts. In this example the L-R or Right only signals end up being modulation with higher modulation frequencies, so tend to spread out the power-frequency spectrum of the result. The first graphic shows this most clearly. I'm afraid I can't comment on what might have been said in this discussion prior to it starting being cross-posted to uk.tech.digital-tv as I haven't seen that. If you or anyone else is simply engaged in a wind-up or trolling I haven't seen that. So if what I write does not fit that context I am not in a position at present to take that into account. Similarly, if 'George' has lost patience as a result of fol-de-rols before this thread popped up here in uk.tech.digital-tv I have no awareness of that, so can't respond on that. Slainte, Jim [1] Indeed infinitely many of them will be of infinitestimally small amplitude. 8-] You could even have wonderful nit-picking debates about if this was 'most' of them, or not, as you can get into playing word-games in English about the relationships between different 'infinity' values and subtracting finite values from them or taking ratios. c.f. discussions in H2G2 about how much it rains. Beyond that I'll leave the question for mathematicians and other theologians. :-) -- Electronics http://www.st-and.ac.uk/~www_pa/Scot...o/electron.htm Audio Misc http://www.audiomisc.co.uk/index.html Armstrong Audio http://www.audiomisc.co.uk/Armstrong/armstrong.html |
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